- 123:36:: 221: ?
a. 52 b. 69
c. 72 d. 25Ans (d)
123 ⇢ 1+2+3 = 6.
62 = 36
Similarly,
221 ⇢ 2+2+1 = 5
52 = 25
2. Sec A + Tan A = 1/3 then what is Sec A - Tan A?
Ans: 3
1+ Tan2 A = Sec2 A = 1
⇒ Sec2 A - Tan2 A =1
⇒ (Sec A + Tan A)(Sec A - Tan A) = 1
⇒ (1/3)(Sec A - Tan A) = 1
⇒ (Sec A - Tan A) = 1(1/3) = 3
3. Train running at 72 kmph how much distance in meters covered in 15 seconds?
Ans: 300 m
To convert 72 Km/h to m/sec* we will multiply it by 5/18. why (1000 m/3600 s)
72*5/18 = 20 m/s
So Train's speed is 20 m/s
So in 15 sec, it will cover a distance equal to,
D= 20*15 = 300 m
4. Sin θ = .......* Cos θ
Ans: Tan θ
Tan θ = Sin θ/Cos θ
⇒ Sin θ = Tan θ*Cos θ
Comparing from questions, black space will be filled byTan θ
5. 100 million dollars is equal to how may indain rupees?
Ans: 6,62,30,00,000 INR#
First know the two basic equations.
1USD= 66.23 INR
1 Million = 10 Lakh (10,00,000)
⇒ 100 million USD = 100*
(10,00,000) = 10,00,00,000
Now we will convert dolloars into Rupee.
As 1 USD = 66.23 INR
⇒ 100 Million USD
= 66.23*10,00,00,000
⇒ 100 million USD= 6,62,30,00,000 INR
# Currency conversion changes daily, so it's best to check the current conversion rates.
6. A. is C, B is D, C is E then what is Z?
Ans: B
A(+2)=C
B(+2)=D
C(+2)=E
Z(+2)=B
7. Tan (-405°)=?
Ans: -1
Tan (-405°)
=Tan (-360°-45)
=Tan (45°) [because tan (360°- θ) = -Tan θ]
= -(1) [because tan(45)= 1]
8. A covers half distance at 3 km/h and another half at doubled speed then how much distance is covered in 6 hrs?
Ans: 20 Km (not 22.5 Km)
Let Distance be = 2x
Half Distance = x @ 3 km/h
Next half distance x @ 6 km/h
when one travels at speed a for half the distance and speed b for other half of the distance.
Average Speed = 2ab/(a+b)
Avg Speed= 2(3)(6)/(3+6) =4 km/h
Distance = Speed*Time
Distance = 4*5 = 20 Km
9. On a Square 100 tree will plant on every side then how many trees are required?
Ans: 396
When you see such questions, take the small numbers and analyze the case.
Let's say we want 4 trees on each side of the square.
So can you say, 4 trees on each side and total will be 4 times 4 that is 16???
No, you can't as you are counting corner trees twice.
What you see now, 2*4 side trees and 1*4 corner tree that is total 12, not 16.
Now in the case of 100 trees on each side, you will get, 98 in middle and 2 being the end points
So total trees = 4*98+4 = 396
General formula = 4*(n-1) for square.
10. Find the next number 1, 1, 4, 8, 9, 27, ?
Ans: 16
The series consists of squares and cubes of consecutive natural numbers i.e.
12, 13, 22, 23, 32, 33, 42, 43
So, missing term = 42 = 16
11. Q=10, FAX = 50 then XEROX =?
Ans: =49
Q=10, FAX =50
Q Comes at 10th position from backward so Q = 10
Similarly, FAX = F+A+X from backward
= 21+26+3=50
Similarly, XEROX =X+E+R+O+X
= 3+22+9+12+3
=49
12. In a certain code, 'PET' is Coded as 64, MET is coded as 52, then SET is coded as:
A. 70 B. 73
C. 76 D. none
Ans: (C) 76
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B
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C
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D
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10th
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K
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15th
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P
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S
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20th
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U
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25th
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26th
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PET = 64
P comes at 16th position
So, 16*2 = 32 and 32*2 = 64
MET = 52
M comes at 13th Position
So, 13*2 = 26 and 26*2 = 52
SET = 76
S comes at 19th Position
So, 19*2 = 38 and 38*2 = 76
13. In total 20 balls, 16 balls are of red color, if they are used for gifts and it should be an equal number of balls in each package of gifts, how many gifts are made?
A. 4 B. 5
C. 6 D. 3
Ans: (A)
The question here itself doesn't seem complete. So we will give our logic.
16 red balls can be divided equally as, 8-8, 4-4-4-4 and lower pairs.
So once we have our 4-4-4-4 pair, we can add the rest 4 odd color balls in each of one.
that means 5-5-5-5
So total 4 pairs.
14. A person sell his radio in 1300 with 30% profit, then what will be the cost price?
Ans: 1000
One thing you can do is, remember the results that is formulas for everything. That is handy sometimes but for rest of us. we will always begin with cost price.
As you know all calculations are made on CP.
Let's calculate the profit.
Profit%=(SP-CP)/CP*100
Let the CP = x
⇒ 30/100 = 1300/x-1
⇒ 130/100 = 1300/x
⇒ x = CP = 1000
15. One selling an article for Rs 270 there is a gian of 12.5%. What is its cost price?
Ans: 240
Gain% = S.P-C.P/C.P*100
⇒ 12.5 =(270-x/x)*100
⇒ 12.5x = 27000 - 100x
⇒ 112.5x = 27000
⇒ x = 240
CP= 240
16. x= 2y, x+y = 25 what is the value of x?
Ans: 50/3
x+y = 25
given x=2y
⇒ 2y+y=25
⇒ 3y=25
⇒y=25/3
⇒ x=2y=50/3
17. If its 10 am in the clock then minute hand and second-hand forms what angle?
Ans: Zero degree
Both Minute hand and Second hand will conside.
Also remember these.
For every hour (i.e.) 60 minutes, the minutes hand travels 360 degrees. So, for 15 minutes, it would have travelled 90 degrees.
For every 12 hours, the hours hand travels 360 degrees. So, for every hour (i.e) 60 minutes, it would have travelled 30 degrees.
18. The Price of 107 cars is Rs 14,44,500 then what is the price of 1 car?
Ans: 13,500
Simple division question. Divisibility rules come handy here.
19. In a mixture a ratio of milk and water is 5:3, if an amount of milk is 25 liters then how much water is there in a mixture?
Ans: 15 liters
M:W = 5:3
So M=5/8 of total mixture
So Total mixture = 25*8/5 = 40
So Water content is = 40-25=15
you can cross check the ratio 25:15 = 5/3
20. The Perimeter of the rectangle is 48 m and length is double of breadth then find the area of the rectangle?
Ans: 128 sq m
Perimeter of the rectangle = 2(l+b) units
Perimeter = 48m
let the breadth be x
length = 2x
48=2(x+2x)
⇒x=8
breadth=8
length=2*8=16
Area of rectangle = 1*b sq units.
21. what is the value of Sec2 Q+2(Tan Q)(Cot Q) - tan2 Q?
Ans: 3
We know tan Q* cot Q = 1
So equation reduces to Sec2 Q+2 -Tan2 Q
We know Sec2 Q -Tan2 Q =1
So (Sec2 Q -Tan2 ) + 2 = 3
22. Cot a=12/5 then (sin a + cos a)Cosec a=?
Ans: 17/5
(Sin a + cos a) cosec a
= (sin a + cos a)/sin a
= sin a/sin a + cos a/sin a
= 1 + cot a
= 1 + 12/5
= 17/5
23. Find the missing number: 3, 4, 6, 8, 9, 12, _, 16
Ans: 12
There are two series,
3, 6, 9, 12
4, 8, 12, 16
24. A man purchases 2 dozen pen at Rs 480 and sells the pack of 4 pens of Rs 100 then Find the Profit %?
Ans: 25%
Cost Price of One pen = 480/24 = Rs. 20
Selling Price of one Pen = 100/4 = Rs. 25
Profit % = (25-20)/20*100
Profit %= 25%
25. BCA: FGE: ? : NOM
Ans: KLJ
Six consecutive alphabets are use, where in each set, we see the rearrangement as follows
ABC ⇒ BCA
EFG ⇒ FGE
JKL ⇒ KLJ
MNO ⇒ NOM
26. How many 5 will occur in 1 to 100?
Ans: 20 times
5, 15, 25 ..... 95 = 10 times
51, 52, ..55, ...59 = 10 times
27. What will be the value of (s+2)3 ?
Ans: s3 + 6s2 + 12s + 8
Cube expenison of (s+2)3 = s3 + 3s2(2) + 3s(2)2 +23
(s+2)3 = s3 + 6s2 + 12s + 8
28. A works double of B and takes 30 days less than B then how many days they both will take to complete the work?
Ans: 20 days
Suppose days taken by A and B are x and 2x respectively.
Given: 2x - x = x = 30
A's one day work = 1/x
B's one day work = 1/2x
(A+B)'s one day work = 1/x + 1/2x = 3/2x
So work will be completed in 2x/ 3days.
From the top we know x is equal to 30
So the work will be completed in 20 days working A and B both together.
29. 3:9 :: 12: ?
Ans: 36 or 144
As options are no given, we can't judge it well.
it ma be 12*3 = 36 or 122 = 144
30. A covers 40 km by 60 kmph and 60 km by 40 kmph, find the average speed?
Ans: 45.15 Km/h
Since unequal distance have been covered in uneven speeds. we will calculate it form the def.
time = Distance/speed
for the first case time = 40/60 = 2/3
for the second case time = 60/40 =3/2
Total distance = 40 + 60 = 100 km
Avg speed = 100/(13/6) = 45.15
31. Cost price of a phone is 11000 and selling price is 13500, find the profit %?
Ans: 22.73
Profit = 13,500 - 11,000 = 2,500
Profit % = 2500/11000*100
Profit % = 22.73%
32. Find the factors of x2 - x - 132?
Ans: x = 12, x = -11
x2 - x - 132=0
Split the middle term
x2 - 12x + 11x - 132=0
x(x-12) + 11(x-12)=0
(x+11)(x-12)=0
x=-11, x=12
33. A can do a work in 10 days and B can do it in 15 days, if they work together for 5 days then A left. In how many more days work will be finished by B?
Ans: 2.5 days
A's one day work = 1/10
B's one day work = 1/15
(A+B)'s one day work
= 1/10 + 1/15
= 5/30 = 1/6
(A+B)'s 5 days work = 5/6
Remaining work = 1/6
B can do the remaining work in
= (15)*1/6 = 5/2 days
34. A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest. What is the rate of interest?
Ans: 6% per annum
Interest = 15,500 - 12,500 = 3,000
we know SI = PRT/100
SI = 3000, P = 12,500, R = ?, T = 4
So R = 3000*100/(4*12500)
R = 6%
35. If M = 14, Tank = 61 then Stardom =?
Ans: 99
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B
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5th
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26th
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M from back is 14th
T from back is 7th
A from back is 26th
K form back is (26-11)+1 = 16th
General rule: (26 - n)+1
Now for
S ⇒ 8
T ⇒ 7 (if you know S is 8, T will be 7)
A ⇒ 26
R ⇒ 9
D ⇒ 23 (you know A is 26, go back for D)
O ⇒ 12 (you know S is 8 count from here)
M ⇒ 14
Total = 99
36. Sin θ = 1/√2 then (tan θ + cot θ )=?
Ans: 2
Sin = P/H so B= √(2-1)=1
So Sides are in the ration P = B = 1 and H = √2
Tan θ = 1
Cot θ = 1
so tan θ + Cot θ = 2
37. Find the factors of x2 +17x + 72 = 0?
Ans: x=-9, x=-8
x2 +8x + 9x + 72 = 0
x(x+8) +9+8)=0
(x+9)(x+8)=0
x=-9, x=-8
38. What is Range of 11, 13, 18, 28, 19, 18, 12, 19?
Ans: 17
The range of a set of data is the difference between the highest and lowest values in the set.
First, arrange the data form highest to lowest value
28, 19, 18, 13, 12, 11
Range = 28-11 =17
39. The value of tan 1125?
Ans: 1
Tan (1125)
=tan(1440 - 315)
= tan (4*360 - 315)
= -tan (315)
= -tan (360 - 45)
= tan(45)= 1
40. Standard Deviation of set (10, 10, 10, 10, 10)?
Ans: Zero
There is no difference between elements so σ value will be 0.
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